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0.5x^2-x=24
We move all terms to the left:
0.5x^2-x-(24)=0
We add all the numbers together, and all the variables
0.5x^2-1x-24=0
a = 0.5; b = -1; c = -24;
Δ = b2-4ac
Δ = -12-4·0.5·(-24)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*0.5}=\frac{-6}{1} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*0.5}=\frac{8}{1} =8 $
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